[LeetCode] Sleep

26 Apr 2024 in Development on Algorithm

• PROBLEMS
  • Description
  • Example
  • Constraints
  • Solution
  • Retrospect

PROBLEMS

Description

---

Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.

Example

---

Example 1:

Input: millis = 100
Output: 100
Explanation: It should return a promise that resolves after 100ms.
let t = Date.now();
sleep(100).then(() => { console.log(Date.now() - t); // 100 });

Example 2:

Input: millis = 200
Output: 200
Explanation: It should return a promise that resolves after 200ms.

Constraints

---

• 1 <= millis <= 1000

Solution

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• Runtime: 51ms
• Memory: 49MB

/**
 * @param {number} millis
 * @return {Promise}
 */
async function sleep(millis) {
    return new Promise((resolve) => {
        setTimeout(() =>{
            resolve(millis)
        }, millis)
    })
}

/**
 * let t = Date.now()
 * sleep(100).then(() => console.log(Date.now() - t)) // 100
 */

Retrospect

---

양의 정수가 파라미터로 들어오면 들어온 파라미터만큼 뒤에 실행되는 Promise객체를 반환하면 되는 문제였고 반환 값은 어떤 것이든 상관 없었다. new Promise를 이용해서 Promise 객체를 생성한 후 setTimeout으로 파라미터로 들어온 양의 정수로 시간 간격을 두고 값을 반환해주었다.